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Find the first five terms of the sequence whose general term is given by π sub π is equal to four π plus one, where π is greater than or equal to one.
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So here is our general term of our sequence.
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And weβre asked to find the first five terms.
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So in order to find terms, we need to plug in values into this general term to find our sequence.
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So where do we begin when plugging in numbers?
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Well, they tell us that π is greater than or equal to one.
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So since itβs equal at one and then greater than one, we can start by plugging in one.
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So we will begin by replacing π with one.
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Four times one plus one.
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Well, four times one is four and four plus one is five.
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So the first term in our sequence is five.
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Now, to find our next term, letβs plug in two.
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Four times two plus one.
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Four times two is eight and eight plus one is nine.
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So our next term in this sequence is nine.
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Now, we plug in three.
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Four times three is 12 and 12 plus one is 13.
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So 13 is our third term.
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Now, we have four times four plus one, which is 16 plus one.
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So our fourth term is 17.
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And then, lastly, we will find our fifth and final term by plugging in five.
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Four times five is 20 and 20 plus one is 21.
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Therefore, the first five terms of this sequence would be five, nine, 13, 17, and 21.