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If a coin is flipped and then a dice is thrown, what is the probability of the coin landing on heads and the die landing on number three?
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We recall that the probability of an event occurring can be written as a fraction.
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The number of successful outcomes is the numerator.
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And the number of possible outcomes is the denominator.
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When flipping a coin, there are two possible outcomes, heads or tails.
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In this question, we need the probability of the coin landing on heads.
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This is equal to one-half or one out of two.
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A fair die is cubic and has numbers one to six on each of its faces.
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This means that there are six possible outcomes.
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The probability of landing on number three is one out of six or one-sixth.
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We need to calculate the probability that both of these events occur.
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The coin needs to land on heads and the die needs to land on three.
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When dealing with probability, the word “and” means multiply.
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We need to multiply the fractions one-half and one-sixth.
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Multiplying the numerators gives us one, and multiplying the denominators gives us 12.
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This means that the probability of the coin landing on heads and the die landing on number three is one-twelfth or one out of 12.