WEBVTT
00:00:02.510 --> 00:00:20.150
Given that 𝐴 is the matrix negative 0.6, negative a half, negative seven over 10, one, and 𝐵 is the matrix negative three over five, negative 0.5, negative 0.7, and one, is it true that 𝐴 is equal to 𝐵?
00:00:22.100 --> 00:00:31.130
Well, for 𝐴 to be equal to 𝐵, then what we need to do is have a look at the individual elements because the corresponding elements in each of our matrices would have to be the same.
00:00:31.130 --> 00:00:34.580
So we can start with our first element.
00:00:35.220 --> 00:00:39.410
So we’ve got negative 0.6 or negative three over five.
00:00:41.160 --> 00:00:44.650
Well, negative 0.6 is equal to negative six over 10.
00:00:46.250 --> 00:00:51.910
Well, if we divide both the numerator and denominator by two, this is gonna give us negative three over five.
00:00:53.890 --> 00:00:56.370
So therefore, we can say that these elements are the same.
00:00:56.710 --> 00:00:58.160
So now let’s move on to our next element.
00:00:59.920 --> 00:01:06.340
Well, if we take a look at our next element, we’ve got negative a half in our matrix 𝐴 and negative 0.5 in matrix 𝐵.
00:01:06.730 --> 00:01:11.200
Well, negative a half is the same as, it’s equal to, negative 0.5.
00:01:11.420 --> 00:01:13.110
So these elements are also the same.
00:01:14.930 --> 00:01:20.130
And then looking at the next element, we’ve got negative seven over 10 or seven-tenths and negative 0.7.
00:01:20.730 --> 00:01:27.110
Well, the first decimal is tenths, so negative 0.7 is the same as negative seven-tenths.
00:01:27.410 --> 00:01:28.660
So these elements are the same.
00:01:30.020 --> 00:01:32.770
And then the final element is just one in each of our matrices.
00:01:33.160 --> 00:01:37.860
So therefore, we can say that it is true, yes, that 𝐴 is equal to 𝐵.