WEBVTT
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By using the linear relation π plus two π equals negative eight, fill in the missing values in the table.
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So we have π values of two and negative eight and one π value of negative three.
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So when π equals two, we donβt know what π is equal to.
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When we donβt know πβs value, we know that π is equal to negative three.
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And when π is equal to negative eight, we donβt know what πβs value is.
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So to find these missing values, we want to use the linear relation π plus two π equals negative eight.
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So letβs begin by solving for π when we know that π is equal to two.
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So we will replace π with two and then solve for π.
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And in order to solve for π, we need to subtract two from both sides of the equation.
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So we have that two π is equal to negative 10 because negative eight minus two is negative 10.
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Now we must divide both sides of the equation by two.
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And now weβve completely isolated π.
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π is equal to negative five because negative 10 divided by two is negative five.
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So when π is two, π is equal to negative five.
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And weβve plugged that in into our table.
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Now letβs solve for π when π equals negative three.
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So we replace π with negative three and we solve for π.
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So first, two times negative three is equal to negative six.
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Now we need to add six to both sides of the equation.
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And we find that π is equal to negative two.
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So when π was negative three, π was equal to negative two.
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Now lastly, when we know that π is equal to negative eight, we need to find what π is equal to.
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So we replace π with negative eight and solve for π.
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So the first thing that we need to do is to add eight to both sides of the equation.
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And we have that two π is equal to zero because negative eight plus eight is zero.
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In isolating π, we divided by two on both sides of the equation and got that π is equal to zero.
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So when π equals negative eight, π equals zero.
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So our missing values were π equals negative five, π equals negative two, and π equals zero.