WEBVTT
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The diagram shows a prism with a cross section of an irregular pentagon.
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On the grid below, draw the front elevation and the side elevation of the prism.
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Use a scale of one square to four meters.
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We can work out the number of squares that correspond to each of the four lengths by dividing by four, as one square is equal to four meters.
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24 meters will be equal to six squares, as 24 divided by four is equal to six.
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In the same way, 16 meters will be equal to four squares.
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14 meters will be equal to three and a half or 3.5 squares.
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And eight meters will be equal to two squares.
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We now need to consider what we would see on the front elevation of the prism.
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The bottom half of the front elevation would be a rectangle, six squares across and two squares up.
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Above this, we would see another rectangle, which would represent the sloping roof.
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This would also be six squares wide, but this time 1.5 or one and a half squares high.
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This means that the full front elevation will be a rectangle, six squares across and 3.5 squares up.
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Six squares is equal to 24 meters.
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And three and a half or 3.5 squares is equal to 14 meters, the height of the prism.
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If we now consider the side elevation, it is clear that we would see a pentagon.
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The pentagon would be four squares wide, as four squares is equal to 16 meters.
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We would then have two parallel sides going up two squares.
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This represents the eight meters.
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Finally, we would have two equal-length diagonal sides that would give a total height of the pentagon of 3.5 squares, as 3.5 squares is equal to 14 meters.
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The front elevation of the prism consists of two rectangles making a larger rectangle.
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And the side elevation consists of a pentagon.