WEBVTT
00:00:01.820 --> 00:00:08.530
Michael had three 𝑥 plus six coins and gave two 𝑥 plus three coins to James.
00:00:09.240 --> 00:00:11.710
How many coins does Michael have left?
00:00:13.500 --> 00:00:19.920
In order to solve this problem, we need to subtract two 𝑥 plus three from three 𝑥 plus six.
00:00:21.310 --> 00:00:29.730
We can do this by grouping or collecting the like terms: three 𝑥 minus two 𝑥 and six minus three.
00:00:31.480 --> 00:00:38.720
Three 𝑥 minus two 𝑥 is equal to 𝑥 and six minus three is equal to three.
00:00:40.110 --> 00:00:48.320
This means that after Michael gave two 𝑥 plus three coins to James, he has 𝑥 plus three coins left.